question_answer

A hollow cylinder with both sides open generates a frequency f in air. When the cylinder vertically immersed into water by half its length the frequency will be

A) f                                             

B) 2f

C) f/2                                         

D)  f/4   

Correct Answer: A

Solution :

(i) Here, \[\frac{\lambda }{2}=l\Rightarrow \lambda =2l\] So, \[{{v}_{1}}=\frac{v}{2l}\]   (ii) And \[\frac{\lambda }{4}=\frac{\ell }{2}\] \[\lambda =\frac{4l}{2}=2l\]                                                                   \[\therefore \] \[{{v}_{2}}=\frac{v}{2l},\]the same