AFMC AFMC Solved Paper-2011

  • question_answer
    A transistor is working in common emitter mode. Its amplification factor\[\left( \beta  \right)\]is 80. If the base current is 250 \[\mu A\], the collector current will be

    A) \[1.25\,\mu A\]                               

    B) \[\frac{250}{80}\,\mu A\]

    C) \[430\,\mu A\]                                 

    D) \[250\times 80\,\mu A\]

    Correct Answer: D

    Solution :

    Current amplification factor, \[\beta =\frac{{{I}_{C}}}{{{I}_{B}}}\] \[\therefore \] \[{{I}_{C}}={{I}_{B}}\times \beta =250\times 80\mu A\]


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