A) \[NC{{l}_{3}}\]and \[HCl\]
B) \[{{N}_{4}}\]and \[N{{H}_{4}}Cl\]
C) \[NC{{l}_{3}}\]and \[N{{H}_{4}}Cl\]
D) \[~{{N}_{2}}\] and \[HCl\]
Correct Answer: A
Solution :
\[N{{H}_{3}}+\underset{\text{excess}}{\mathop{2C{{l}_{2}}}}\,\xrightarrow[{}]{{}}\underset{(explosive)}{\mathop{NC{{l}_{3}}}}\,+3HCl\]
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