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AFMC AFMC Solved Paper-2010

  • question_answer
    If 1 mole of an ideal gas expands isothermally at \[37{{\,}^{o}}C\]from 15 L to 25 L, the maximum work obtained is

    A)  12.87 J                                 

    B)  6.43 J

    C)  8.57 J                                   

    D)  2.92 J

    Correct Answer: A

    Solution :

                     \[{{W}_{\text{rev}}}=-2.303nRT\log \frac{{{V}_{2}}}{{{V}_{1}}}\] \[=-2.303\times 1\times 0.0821\times (273+37)log\frac{25}{15}\] \[=-2.303\times 0.0821\times 310\log \frac{5}{3}\] = 13 J =12.87 J


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