A) \[C{{u}^{+}}\]
B) \[{{V}^{3+}}\]
C) \[C{{o}^{2+}}\]
D) \[N{{i}^{2+}}\]
Correct Answer: A
Solution :
Presence of unpaired electron is a necessity for transition metal ions to give colour. The electronic configuration of given transition metal ions are as \[_{29}C{{u}^{+}}=[Ar]3{{d}^{10}}4{{s}^{0}}\] (no unpaired electron) \[_{23}{{V}^{3+}}=[Ar]3{{d}^{2}}4{{s}^{0}}\] (two unpaired electrons) \[_{27}C{{o}^{2+}}=[Ar]3{{d}^{2}}4{{s}^{0}}\] (three unpaired electrons) \[_{28}N{{i}^{2+}}=[Ar]\,3{{d}^{8}}4{{s}^{0}}\] (two unpaired electrons) Thus, \[C{{u}^{+}}\]ion is colourless.
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