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AFMC AFMC Solved Paper-2010

  • question_answer
    Figure shows a uniform rod of length 30 cm having a mass of 3.0 kg. The strings shown in the figure are pulled by constant forces of 20 N and 32 N. Find the force exerted by 20 cm part of the rod on the 10 cm pan. All the surfaces are smooth and the strings and pulleys are light

    A) 36 N                                      

    B) 12 N

    C) 64 N                                      

    D) 24 N

    Correct Answer: D

    Solution :

    Net force on the rod, \[f=32-20=12\,\text{N}\] Acceleration of rod \[=\frac{f}{m}=\frac{12}{3}=4\,m{{s}^{-2}}\] Equation of motion of 10 cm part is \[F-20=m\times a=1\times 4\] \[F=4+20=24\,N\] Similarly, Equation of motion 20 cm part is \[32-F=m'\,a=2\times 4\] \[F=32-8=24\,N\]


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