A) \[Pb{{(N{{O}_{3}})}_{2}}+N{{O}_{2}}\]
B) \[PbN{{O}_{3}}+NO\]
C) \[Pb{{(N{{O}_{3}})}_{4}}+N{{O}_{3}}\]
D) \[Pb{{(N{{O}_{3}})}_{3}}+{{N}_{2}}O\]
Correct Answer: A
Solution :
\[Pb+conc.HN{{O}_{3}}\xrightarrow[{}]{{}}Pb{{(N{{O}_{3}})}_{2}}+N{{O}_{2}}\]
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