A) \[\pi /2\]
B) \[\pi /4\]
C) \[\pi /6\]
D) \[\pi /8\]
Correct Answer: A
Solution :
Use \[\omega ={{\omega }_{0}}-\alpha t\] Here, \[{{\omega }_{0}}=900\,rpm\,\,=\,(2\pi \times 900)/60\,\,rad\,{{s}^{-1}}\] \[\omega =0\] and \[t=60\] \[\therefore \] \[0=\frac{2\pi \times 900}{60}-60\alpha \] or \[\alpha =\frac{2\pi \times 900}{60\times 60}\] \[\alpha =\frac{\pi }{2}\]
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