A) 0.178\[\Omega \]
B) 0.002\[\Omega \]
C) 0.0060\[\Omega \]
D) 5\[\Omega \]
Correct Answer: C
Solution :
Resistance of shunt needed to convent it into ammeter is \[S=\frac{{{I}_{g}}G}{I-{{I}_{g}}}\] \[=\frac{2\times {{10}^{-3}}\times 15}{5-2\times {{10}^{-3}}}=0.006\,\Omega \]
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