A) 6 component capacitors
B) 12 component capacitors
C) 72 component capacitors
D) 2 component capacitors
Correct Answer: C
Solution :
Minimum number of condensers in each row \[=\frac{3000}{500}=6\] If \[{{C}_{s}}\]is capacity of 6 condensers in a row, \[\frac{1}{{{C}_{s}}}=\frac{1}{1}+\frac{1}{1}+\frac{1}{1}+\frac{1}{1}+\frac{1}{1}+\frac{1}{1}=6\] \[{{C}_{s}}=\frac{1}{6}\mu F\] Let there be m such rows in parallel, Total capacity \[=m\times {{C}_{s}}\] \[2=m\times \frac{1}{6}\] \[\therefore \] \[m=12\] Total number of capacitors \[=6\times 12\] \[=72\]
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