A) \[16\times {{10}^{-32}}J\]
B) \[31\times {{10}^{-26}}J\]
C) \[4\times {{10}^{-10}}J\]
D) \[32\times {{10}^{-32}}J\]
Correct Answer: D
Solution :
Here, \[q=8\times {{10}^{-18}}C,C=100\mu F={{10}^{-4}}F\] \[V=\frac{q}{C}=\frac{8\times {{10}^{-18}}}{{{10}^{-4}}}\] \[=8\times {{10}^{-14}}\text{ volt}\] Work done \[=\frac{1}{2}qV\] \[=\frac{1}{2}\times 8\times {{10}^{-18}}\times 8\times {{10}^{-14}}\] \[=32\times {{10}^{-32}}\text{J}\]
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