AFMC AFMC Solved Paper-2010

  • question_answer
    The half- life of radioactive radon is 3.8 days. The time at the end of which (1/20)th of the radon sample will remain undecayed is (Given\[{{\log }_{10}}e=-0.4343\]).

    A) 13.8 days                            

    B) 16.5 days

    C) 33 days                                

    D) 76 days

    Correct Answer: B

    Solution :

    By formula, \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{t/{{T}_{1/2}}}}\] \[{{\left( \frac{1}{2} \right)}^{n}}=\frac{N}{{{N}_{0}}}=\frac{1}{20}\]gives \[n=4.3\] \[t=nT=4.3\times 3.8\approx 16.5\]days


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