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AFMC AFMC Solved Paper-2010

  • question_answer
    The Young's double slit experiment is performed with blue and with green light of wavelengths 4360\[{{A}^{o}}\]and    5460 \[{{A}^{o}}\]respectively. If x is the distance of 4th maxima from the central one, then

    A) \[{{X}_{(blue)}}={{x}_{(green)}}\]

    B) \[{{X}_{(blue)}}>{{x}_{(green)}}\]

    C) \[{{X}_{(blue)}}<{{x}_{(green)}}\]

    D) \[{{X}_{(blue)}}{{^{/x}}_{(green)}}=5460/4360\]

    Correct Answer: C

    Solution :

    Distance of nth maxima, \[x=n\lambda \frac{D}{d}\propto \lambda \] As,       \[{{\lambda }_{b}}<{{\lambda }_{g}}\] \[\therefore \]    \[{{x}_{blue}}<{{x}_{green}}\]


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