AFMC AFMC Solved Paper-2010

  • question_answer
    A plane electromagnetic wave propagating in the X-direction has wavelength of 6.0 mm. The electric field is in the V-direction and its maximum magnitude is 33 Vm-1. The equation for the electric field as function of x and f is

    A) \[11\,\sin \,\pi \left( t-x/c \right)\]

    B) \[33\,\sin \,\pi \times {{10}^{11}}\left( t-x/c \right)\]

    C) \[33\,\sin \,\pi \left( t-x/c \right)\]

    D) \[11\,\sin \,\pi \times {{10}^{11}}\left( t-x/c \right)\]

    Correct Answer: B

    Solution :

    Angular frequency \[\omega =2\pi v=\frac{2\pi c}{\lambda }=\frac{2\pi \times 3\times {{10}^{8}}}{6\times {{10}^{-}}3}\] \[=\pi \times {{10}^{11}}\,rad{{s}^{-1}}\] The equation for the electric field, along Y-axis in the electromagnetic wave is \[{{E}_{y}}={{E}_{0}}\sin \omega \left( t-\frac{x}{c} \right)\] \[=33\sin \pi \times {{10}^{11}}(t-x/c)\]


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