AFMC AFMC Solved Paper-2010

  • question_answer
    If the supply of oxygen is limited, \[{{H}_{2}}S\]reacts with \[{{O}_{2}}\] to form

    A)  \[{{H}_{2}}O+S{{O}_{3}}\]          

    B)  \[{{H}_{2}}O+S\]

    C)   \[{{H}_{2}}S{{O}_{4}}+S\]          

    D)  \[~{{H}_{2}}O+S{{O}_{2}}\]

    Correct Answer: B

    Solution :

                     In limited supply of oxygen, \[{{\text{H}}_{\text{2}}}\text{S}\] bums with blue flame and S and \[{{\text{H}}_{\text{2}}}\text{O}\] are the main products. \[2{{H}_{2}}S+{{O}_{2}}\xrightarrow[{}]{{}}2{{H}_{2}}O+2S\] Note: In excess of oxygen, \[{{\text{H}}_{\text{2}}}\text{S}\] gives \[\text{S}{{\text{O}}_{\text{2}}}\] and water as main product.


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