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AFMC AFMC Solved Paper-2009

  • question_answer
    By the ideal gas law, the pressure of 0.60  mole \[\text{N}{{\text{H}}_{\text{3}}}\]gas in a 3.00 L vessel at \[25{{\,}^{o}}C\] is

    A) 48.9 atm                              

    B) 4.89 atm

    C) 0.489 arm           

    D) 489 atm

    Correct Answer: B

    Solution :

    \[pV=nRT\] or            \[p=\frac{nRT}{V}\] \[=\frac{0.60\times 0.0821\times 298}{3}\] \[=4.89\,\text{atm}\]


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