question_answer

A particle of mass m moves in a circular path radius r under the action of a force \[\frac{m{{v}^{2}}}{r}\].The work done during its motion over half of the circumference of the circular path will be

A) \[\left( \frac{m{{v}^{2}}}{r} \right)\times 2\pi r\]                              

B) \[\left( \frac{m{{v}^{2}}}{r} \right)\times \pi r\]

C) \[\frac{\left( 2\pi r \right)}{\left( \frac{m{{v}^{2}}}{r} \right)}\]                                  

D) zero