A) \[\frac{V}{n}\]
B) nV
C) nV2
D) n2/3 V
Correct Answer: D
Solution :
Suppose we have n identical drops each having radius r, capacitance C, charge q and potential V. If these drops are combined to form a big drop of radius R, capacitance C', charge Q and potential V will become : Charge on big drop \[Q=nq\] Capacitance of big drop \[C'={{n}^{1/3}}C\] Hence potential of big drop \[V'=\frac{Q}{C'}\] \[=\frac{nq}{{{n}^{1/3}}C}\] \[={{n}^{2/3}}V\]
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