AFMC AFMC Solved Paper-2009

  • question_answer
    What is the current through an ideal pn - junction diode shown in figure below?

    A) Zero                                      

    B) 10 mA

    C) 20 mA                                  

    D) 50 mA

    Correct Answer: C

    Solution :

    The potential of p-side is more positive than that of n-side, hence, diode is in forward biasing. In forward biasing current flow is possible and \[I=\frac{V}{R}\]\[=\frac{(3-1)}{100}\]\[\text{= 20}\,\text{mA}\]


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