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AFMC AFMC Solved Paper-2008

  • question_answer
    In the conversion of \[B{{r}^{2}}\]to \[BrO_{3}^{-},\]the oxidation number of Br changes from

    A)  zero to +5                          

    B)  +1 to +5

    C)  zero to -3                           

    D)  +2 to -1-5

    Correct Answer: A

    Solution :

                     Bromine has zero oxidation state because it is in free state \[B{{\overset{0}{\mathop{r}}\,}_{2}}\xrightarrow{{}}BrO_{3}^{-}\] \[BrO_{3}^{-}\] \[x+(-2\times 3)=-1\] \[x+(-6)=-1\] \[x=+\,6-1\] \[=+\,5\]                 So, oxidation number changes from 0 to + 5.


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