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AFMC AFMC Solved Paper-2008

  • question_answer
    0.01 mole of a non-electrolyte is dissolved in 10 g of water. The molality of the solution is

    A)  0.1 m                                   

    B)  0.5 m

    C)  1.0m                                    

    D)  0.18m

    Correct Answer: C

    Solution :

                     \[\text{Molality (m) = }\frac{\text{number of moles of solute}}{\text{weight of solvent in kg}}\] \[=\frac{0.01}{10\times {{10}^{-3}}}\] \[=\frac{0.01\times {{10}^{3}}}{10}\] = 1 m


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