A) \[{{C}_{2}}{{H}_{5}}OH\]
B) \[C{{H}_{3}}OC{{H}_{3}}\]
C) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]
D) \[C{{H}_{3}}O{{C}_{2}}{{H}_{5}}\]
Correct Answer: C
Solution :
Diethyl ether when heated with CO at \[\text{150}{{\,}^{\text{o}}}\text{C}\] and 500 atm pressure in presence of \[\text{B}{{\text{F}}_{\text{3}}}\] forms ethyl propionate. \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+CO\frac{{{150}^{o}}C\Delta }{500\,atm}\underset{ethyl\,propionate}{\mathop{{{C}_{2}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}}}\,\]
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