A) 662
B) 1324
C) 66.2
D) 6.62
Correct Answer: A
Solution :
\[E=3\times {{10}^{-12}}\text{erg}\] \[\lambda =?\] \[h=6.62\times {{10}^{-27}}\,\text{erg}-\text{s}\] \[c=3\times 10{{\,}^{10}}\text{cm }{{\text{s}}^{-1}}\] \[E=\frac{hc}{\lambda }\] \[3\times {{10}^{-2}}=\frac{6.62\times {{10}^{-27}}\times 3\times {{10}^{10}}}{\lambda }\] \[\lambda =\frac{6.62\times {{10}^{-27}}\times 3\times {{10}^{10}}}{3\times {{10}^{-12}}}\] \[=6.62\times {{10}^{-5}}\,\text{cm}\] \[=662\times {{10}^{-7}}\,\text{cm}\] \[=662\times {{10}^{-9}}\,\text{m}\,\text{= 662}\,\text{nm}\]
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