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AFMC AFMC Solved Paper-2008

  • question_answer
    The equation of a simple harmonic wave is given by y = 5 sin \[\frac{\pi }{2}\] (100t - x), where x and y are in metre and time is in second. The period of the wave in second will be

    A) 0.04                                       

    B) 0.01

    C) 1                                             

    D) 5

    Correct Answer: A

    Solution :

    The given equation is \[y=5\sin \frac{\pi }{2}(100t-x)\]                                               ?(i) Comparing Eq. (i) with standard wave equation, given by \[y=A\sin (\omega t-kx)\]                                            ?(ii) we have \[\omega =\frac{100\pi }{2}=50\pi \] \[\Rightarrow \]      \[\frac{2\pi }{T}=50\pi \] \[\Rightarrow \]      \[T=\frac{2\pi }{50\pi }=0.04s\]


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