A) \[\frac{x}{m}=k{{p}^{1/n}}\]
B) \[x=mk{{p}^{1/n}}\]
C) \[\frac{x}{m}=k{{p}^{-n}}\]
D) all of these
Correct Answer: D
Solution :
Freundlich adsorption isotherm \[\frac{x}{m}=k{{p}^{1/n}}\] Here, \[\frac{x}{m}=\]amount of gas adsorbed by adsorbent per gram k and n = constant p = pressure Other forms are \[x=mk{{p}^{1/n}}\] \[\frac{x}{m}=k{{p}^{-n}}\]
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