A) The lift was in constant motion upwards
B) The lift was in constant modal downwards
C) The lift while in constant motion upwards, is stopped suddenly
D) The lift while in constant motto downwards, is suddenly stopped
Correct Answer: C
Solution :
For upward acceleration apparent weight= m (g + a) If lift suddenly stops during upward motion then apparent weight =m(g-a) because instead of acceleration, we will consider retardation. In the problem it is given that scale reading initially was 60 kg and due to sudden jerk reading decreases and finally comes back to the original mark ie, 60 kg. So, we can conclude that lift was moving upwards with constant speed and suddenly stops.
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