AFMC AFMC Solved Paper-2006

  • question_answer
    The change in entropy for the fusion, of 1 mole of ice is [mp of ice = 273 K, molar enthalpy of fusion for ice\[=6.0\,kJ\,mo{{l}^{-1}}\]]

    A) \[11.73\text{ }J{{K}^{-1}}\text{ }mo{{l}^{-1}}\]

    B) \[18.84\text{ }J{{K}^{-1}}\text{ }mo{{l}^{-1}}\]

    C) \[~21.97J{{K}^{-1}}\text{ }mo{{l}^{-1}}\]

    D) \[24.47\text{ }J{{K}^{-1}}\text{ }mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

    Entropy change of fusion \[\Delta {{S}_{f}}=\frac{\Delta {{H}_{f}}}{T}\] \[\Delta {{H}_{f}}=60\times {{10}^{3}}J,\,mo{{l}^{-1}},\,T=273\,K\] \[\Delta {{S}_{f}}=\frac{60\times {{10}^{3}}}{273}\] \[=21.97\,J\,{{K}^{-1}}mo{{l}^{-1}}\]


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