A) 2.5
B) 3
C) 5
D) 7.5
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} 2\,mole \\ 2\times 18 \\ =36\,g \end{smallmatrix}}{\mathop{2{{H}_{2}}O}}\,\,\xrightarrow{Electrolysis}2{{H}_{2}}+\underset{1\,mole}{\mathop{{{O}_{2}}}}\,\] \[\because \]36 g of \[{{\text{H}}_{\text{2}}}\text{O}\]produce 1 mole of oxygen \[\therefore \] 108 g of water will produce oxygen \[=\frac{108}{36}=\,mol\]
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