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AFMC AFMC Solved Paper-2006

  • question_answer
    The oxidation number of nitrogen in \[\text{NaN}{{\text{O}}_{\text{2}}}\]is:

    A) \[\text{+3}\]                                     

    B) +5

    C) -3                                           

    D) -5

    Correct Answer: A

    Solution :

    Let the oxidation number of nitrogen in  \[\text{NaN}{{\text{O}}_{\text{2}}}\] is \[x\] \[\therefore \]  \[1+x+2(-2)=0\]                 \[1+x-4=0\]                 \[x=+3\]


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