AFMC AFMC Solved Paper-2006

  • question_answer
    When a charged particle moving with velocity \[\overrightarrow{v}\] is subjected to a magnetic field of induction\[\overrightarrow{B,}\]the force on it is non-zero. This implies that:

    A) angle between \[\overrightarrow{v}\] and \[\overrightarrow{B,}\]is necessarily 90°

    B) angle between \[\overrightarrow{v}\] and \[\overrightarrow{B,}\]can have any value other than 90°

    C) angle between \[\overrightarrow{v}\] and \[\overrightarrow{B,}\] can have any value other than zero and 180°

    D)  angle between \[\overrightarrow{v}\] and \[\overrightarrow{B,}\] is either zero or 180°

    Correct Answer: C

    Solution :

    When a charged particle q is moving in a uniform magnetic field\[\vec{B}\] with velocity \[\vec{v}\] such that angle between \[\vec{v}\]and \[\vec{B}\]be \[\theta ,\] then due to interaction between the magnetic field produced due to moving charge and magnetic force applied, the charge q experiences a force which is given by                 \[F=qvB\sin \theta \] If \[\theta ={{0}^{0}}\]or \[{{180}^{0}},\]then \[\sin \theta =0\] \[\therefore \]    \[F=qvB\sin \theta =0\] Since, force on charged particle is non-zero, so angle between \[\vec{v}\]and\[\vec{B}\] can have any value other than zero and \[{{180}^{o}}.\] Note: Force experienced by the charged  particle is Lorentz force.


You need to login to perform this action.
You will be redirected in 3 sec spinner