A) no interference
B) interference with bright band
C) interference with dark bands
D) interference in which breadth of the fringe will be slightly increased
Correct Answer: D
Solution :
When chamber is evacuated, the refractive index \[(\mu )\] decreases. Therefore, wavelength \[\left( \lambda \propto \frac{1}{\mu } \right)\] increases. Now, fringe width is given by \[\beta =\frac{\lambda D}{d}\]\[\Rightarrow \] \[\beta \propto \lambda \] Therefore, as wavelength increases, the fringe width will increase.
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