A) ethanoic acid
B) methanoic acid
C) propanoic acid
D) either (a) or (c)
Correct Answer: C
Solution :
Sodium salt of any carboxylic acid with hot soda lime undergo decarboxylation to form alkane which has one carbon atom less than the parent molecule. \[{{C}_{2}}{{H}_{5}}\xrightarrow[\Delta ]{NaOH/CaO}{{C}_{2}}{{H}_{6}}\uparrow N{{a}_{2}}C{{O}_{3}}\]
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