AFMC AFMC Solved Paper-2005

  • question_answer
    The product obtained on reaction of \[{{C}_{2}}{{H}_{5}}Cl\]with hydrogen over palladium carbon is :

    A) \[{{C}_{3}}{{H}_{8}}\]                    

    B) \[{{C}_{4}}{{H}_{10}}\]

    C) \[{{C}_{2}}{{H}_{6}}\]                    

    D) \[{{C}_{2}}{{H}_{4}}\]

    Correct Answer: C

    Solution :

    \[\underset{(X=Br,\,I)}{\mathop{RX}}\,\xrightarrow[Zn/HCl\,orZn/Cu/{{C}_{2}}{{H}_{5}}OH]{{{H}_{2}}/Pd\,or}\underset{alkane}{\mathop{RH}}\,+HX\] \[{{C}_{2}}{{H}_{5}}Cl\frac{any\,of\,the\,above}{regents}\underset{Ethane}{\mathop{{{C}_{2}}{{H}_{6}}}}\,+HCl\]


You need to login to perform this action.
You will be redirected in 3 sec spinner