A) 1N
B) 0.1 N
C) 10 N
D) 11 N
Correct Answer: B
Solution :
\[\text{Malarity = 0}\text{.5}\,\text{M}\] \[{{\text{V}}_{\text{1}}}\text{= 1}\,\text{L}\] \[{{\text{V}}_{2}}\text{= 10}\,\text{L}\] \[\text{Normality = molarity }\!\!\times\!\!\text{ basicity}\] \[\therefore \] \[{{N}_{1}}=0.5\times 2\][\[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]has tow replaceable H \[\text{=1N}\] atoms so, basicity is 2] According to law of dilution \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[1\times 1={{N}_{2}}\times 10\] \[{{N}_{2}}=0.1\,N\]i.e., decinormal
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