A) 10 mL of\[{{H}_{2}}\]
B) 5 mL of \[{{H}_{2}}\]
C) 10 mL of \[{{O}_{2}}\]
D) 5 mL of \[{{O}_{2}}\]
Correct Answer: D
Solution :
Hydrogen and oxygen reacts as follows \[\underset{30\,mL}{\mathop{\underset{2\,vol}{\mathop{\underset{2mole}{\mathop{2{{H}_{2}}O}}\,\,}}\,}}\,+\underset{15\,mL}{\mathop{\underset{1\,vol}{\mathop{\underset{1\,mole}{\mathop{{{O}_{2}}}}\,}}\,}}\,\xrightarrow{{}}\underset{30\,mL}{\mathop{\underset{2\,vol}{\mathop{\underset{2\,mole}{\mathop{2{{H}_{2}}O}}\,}}\,}}\,\] Here hydrogen is the limiting reagent as it is completely consumed and oxygen is the excess reagent. Oxygen left \[=20\,mL\,-15\,mL=5mL\]
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