A) carbonium ion
B) alkoxyion
C) alkyl hydrogen sulphate
D) none of the above
Correct Answer: A
Solution :
Cone. \[\text{H2S}{{\text{O}}_{\text{4}}}\]is an excellent dehydrating agent. Upon reaction with an alcohol it forms an alkene and water molecule is given out. First step involves protonation of alcohol. \[{{-}^{\beta }}\underset{|}{\overset{|}{\mathop{C}}}\,-\underset{|}{\overset{|}{\mathop{{{C}^{\alpha }}}}}\,-OH-{{H}^{+}}\xrightarrow{{}}\] \[\left[ -\underset{|}{\overset{|}{\mathop{C}}}\,-\underset{unstable}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}\,-\overset{+}{\mathop{O}}\,{{H}_{2}} \right]\underset{Carbonium\,Carbocatioin}{\mathop{\xrightarrow{-{{H}_{2}}O}-\underset{|}{\overset{|}{\mathop{^{\beta }C}}}\,-\underset{|}{\overset{|}{\mathop{^{\alpha }{{C}^{+}}}}}\,}}\,\] Which on dehydration forms carbonium ion.
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