A) 1/4
B) 1/8
C) 1/16
D) 1/32
Correct Answer: C
Solution :
The time in which mass of a radioactive substance remains half of its initial mass is known as its half life \[({{t}_{1/2}}).\] \[{{t}_{1/2}}=\frac{0.693}{\lambda }\] (disintegration constant) Half-life is independent of temperature, pressure and number of atoms present initially. \[{{\text{T}}_{\text{1/2}}}\]of a non radioactive substance is infinity Half-life \[{{t}_{1/2}}=3\,\]days Total time = 12 days \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\]where \[{{N}_{0}}=\]Initial amount \[N=\]Amount left after disintegration \[n=\frac{Total\,time}{Half-life}\]n = number of half life \[=\frac{12}{3}=4\] \[N={{\left( \frac{1}{2} \right)}^{4}}\] \[=\frac{1}{16}\]
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