AFMC AFMC Solved Paper-2005

  • question_answer
    Consider the following equation of Bernoulli's theorem \[P+\frac{1}{2}\rho {{v}^{2}}+\rho gh=K\left( cons\tan t \right)\] The dimensions of K/P are same as that of which of the following?

    A) Thrust                                  

    B) Pressure

    C) Angle                                   

    D) Viscosity

    Correct Answer: C

    Solution :

    Key Idea: Only quantities possessing similar dimensions can be added. The given equation of Bernoulli's theorem is \[P+\frac{1}{2}\rho {{v}^{2}}+\rho gh=K\]where P is pressure, \[\rho \] is density, g is acceleration due to gravity and h is height. We know that every equation relating  physical quantities should be in dimensional balance. It means dimensions of terms on both sides must be same. Hence, K has same dimensions as P and so \[\frac{K}{P}\] is dimensionless. Out of the given four options angle is a dimensionless quantity.


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