AFMC AFMC Solved Paper-2005

  • question_answer
    "Pascal-second" has the dimensions of:

    A) force                                    

    B) energy

    C) pressure                                             

    D) coefficient of viscosity

    Correct Answer: D

    Solution :

    Key Idea: Pascal is unit of pressure. Pascal is unit of pressure, hence its dimensional formula is\[[M{{L}^{-1}}{{T}^{-2}}]\] \[\therefore \]  Dimensional formula of Pascal-second is \[[M{{L}^{-1}}{{T}^{-1}}]\] From the formula of coefficient of viscosity, we have\[\eta =\frac{F}{A(\Delta v/\Delta z)}\]where F is force, A is area and \[\frac{\Delta v}{\Delta z}\] is velocity gradient. \[\therefore \] Dimensions of \[\eta =\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}][L{{T}^{-1}}/L]}\]                          \[=[M{{L}^{-1}}{{T}^{-1}}]\] Hence, Pascal-second has dimensions of coefficient of viscosity.


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