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AFMC AFMC Solved Paper-2004

  • question_answer
    Containers A and B have same gases. Pressure volume and temperature of A are all twice that of B, then the ratio of number of molecules of A and B are :

    A) 1:2                         

    B) 2:1

    C) 1:4                         

    D) 4 : 1

    Correct Answer: B

    Solution :

    Under similar conditions of temperature and pressure equal volume of gases contains equal number of molecules.  
    For B For A
    \[{{P}_{B}}=P\] \[{{P}_{A}}=2P\]
    \[{{V}_{B}}=V\] \[{{V}_{A}}=2V\]
    \[{{T}_{B}}=T\] \[{{T}_{A}}=2T\]
    According to Gas law \[\frac{{{P}_{A}}{{V}_{A}}}{{{n}_{A}}R{{T}_{A}}}=\frac{{{P}_{B}}{{V}_{B}}}{{{n}_{B}}{{T}_{B}}R}\] \[\frac{2P\times 2V}{{{n}_{A}}R.2T}=\frac{PV}{n{{ & }_{B}}RT}\] \[\frac{{{n}_{A}}}{{{n}_{B}}}=\frac{2}{1}\] no. of molecules = mole\[\times \]Avogadro?s no. \[\Rightarrow \]\[\frac{molecules\,A}{molecules\,of\,B}=\frac{2\times {{N}_{A}}}{1\times {{N}_{A}}}=\frac{2}{1}\]


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