A) 4 m/s
B) 2 m/s
C) 8 m/s
D) 1 m/s
Correct Answer: D
Solution :
Key Idea: Total momentum of boat + dog system is conserved. From law of conservation of linear momentum, momentum of boat = momentum of dog \[{{m}_{1}}{{v}_{2}}={{m}_{2}}{{v}_{2}}\] Given, \[{{m}_{1}}=40\,kg\] \[v{{ & }_{1}}=?\,{{m}_{2}}=\,4\,kg,\,{{v}_{2}}=10m/s\] \[\therefore \] \[40\times {{v}_{1}}=4\times 10\] \[\Rightarrow \] \[{{v}_{1}}=\frac{4\times 10}{40}=1\,m/s\]
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