AFMC AFMC Solved Paper-2004

  • question_answer
    Unit of reduction factor is:

    A) ampere                               

    B) ohm

    C)  tesia                                    

    D) weber

    Correct Answer: A

    Solution :

    In a suspended coil galvanometer the strength of current is not proportional to the deflection \[\text{o }\!\!|\!\!\text{ }\]hence, cannot be read directly. To remove this difficulty the field is made radial. Hence, deflecting torque on the coil suspended in radial magnetic field is \[NiAB\] where N is number of turns in coil, A is area of plane of coil and B is magnetic field. \[NiAB=C\text{o }\!\!|\!\!\text{ }\] \[\Rightarrow \]            \[i=\frac{C}{NAB}\text{o }\!\!|\!\!\text{ }\] \[\Rightarrow \]           \[i=K\text{o }\!\!|\!\!\text{ }\] where K is a constant called reduction factor. Its unit is same as of current that is ampere.


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