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AFMC AFMC Solved Paper-2003

  • question_answer
    If the concentration of the reactant are doubled in a reversible chemical equation having two reactant (in equilibrium) then the equilibrium constant will:

    A) become one fourth

    B) doubled

    C) halved

    D) remains same

    Correct Answer: A

    Solution :

    The equilibrium constant becomes one fourth because it is inversely proportional to the concentration of reactants. For a general equation \[A+BC+D\] \[{{K}_{c}}=\frac{[C][D]}{[A][B]}\] If concentration of A and B are doubled then            \[{{K}_{c}}=\frac{[C][D]}{2[A]2[B]}=\frac{1}{4}{{K}_{c}}\]


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