A) nitrolim
B) calcium ammonium nitrate
C) ammonium sulphate
D) urea
Correct Answer: D
Solution :
Maximum percent of N is in urea \[(N{{H}_{2}}CON{{H}_{2}})\] N% in urea \[=\frac{mass\,of\,{{N}_{2}}}{mol.\,mass\,of\,urea}\times 100\] \[\frac{28}{60}\times 100=46.7%\] Ammonium sulphate contains 21% of nitrogen Ammonium sulphate \[{{(N{{H}_{4}})}_{2}}S{{O}_{4}}\] \[N%=\frac{38}{132}\times 100=21.21%\]
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