A) \[FeS{{O}_{4}}\]
B) \[FeS{{O}_{3}}\]
C) \[Fe{{(S{{O}_{4}})}_{2}}\]
D) \[F{{e}_{2}}{{(S{{O}_{4}})}_{3}}\]
Correct Answer: D
Solution :
Ferric sulphate is\[F{{e}_{2}}{{(S{{O}_{4}})}_{3}},\] iron exists in two oxidation states + 2 (ferrous and + 3 (ferric) \[FeS{{O}_{4}}=\]ferrous sulphate \[FeS{{O}_{3}}=\]Ferrous sulphite
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