A) 1 L of molecule
B) 1 g of molecules
C) gram molecular mass
D) 1 g atom of molecules
Correct Answer: C
Solution :
Avogardo?s number \[(6.023\times {{10}^{23}})\] is the number of molecules present in 12 g of \[{{C}^{12}}\]isotope of carbon 1 mole of any/substance (at STP) contains \[6.023\times {{10}^{23}}\] molecules 1 mole = gram/molecular mass of a substance \[=32g\,{{O}_{2}}\] \[=2\,g\,{{H}_{2}}\]etc.
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