question_answer

The geometry of \[{{[Ni{{(CN)}_{4}}]}^{2-}}\]  and \[{{[NiC{{l}_{4}}]}^{2-}}\] ions are:

A)  tetrahedral

B) square planar

C) square planar and tetrahedral respectively

D) tetrahedral and square planar respectively

Correct Answer: C

Solution :

The geometry of \[{{[Ni{{(CN)}_{4}}]}^{2-}}\] is square planar and\[{{[NiC{{l}_{4}}]}^{2-}}\] is tetrahedral \[\text{C}{{\text{N}}^{-}}\]is a strong ligand (crystal field theory) hence it cause the pairing of electron in \[\text{N}{{\text{i}}^{\text{2+}}}\]while \[\text{C}{{\text{l}}^{-}}\]is a weak ligand so it does not cause pairing of electrons