A) 0.400 N
B) 0.899 N
C) 0.040 N
D) 0.080 N
Correct Answer: D
Solution :
According to law of dilution\[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] (equivalent before and after dilution remains same) \[{{V}_{1}}=250\,mL\,\,{{V}_{2}}=1000+250=1250\,mL\] \[0.4\times 250=1250\times {{N}_{2}}\] \[\frac{0.4\times 250}{1250}={{N}_{2}}\] \[{{N}_{2}}=0.08\,N\] Normality of a solution is defined as the number of gram equivalent of solute present in one litre of the solution or milli equivalents of solute present in one milli litre of the solution \[N=\frac{gram\,e\,quivalent\,of\,solute}{vol.of\,sol.(L)}\] \[N=\frac{mass\,o\,fsolute}{equivalent\,wt.of\,solute\,molecule}\] \[\div \] vol of solution (L) Solution may be normal 1N, decinormal \[(1/10N),\] centinormal \[(1/100\,N)\]etc.
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