A) is doubled
B) is halved
C) becomes four times
D) becomes 1/4 times
Correct Answer: D
Solution :
A body performing circular motion is acted upon by a force which is always directed towards the centre of the circle. This force is called centripetal force. If m is mass, v is velocity and r is radius of circular path then \[F=\frac{m{{v}^{2}}}{r}\] \[\Rightarrow \] \[F\propto {{v}^{2}}\]When speed is doubled i.e., (2 v) then \[F'\propto {{(2v)}^{2}}\] \[F'\propto 4{{v}^{2}}\] Hence, chance of over tunning becames \[\frac{1}{4}\]times.
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