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AFMC AFMC Solved Paper-2002

  • question_answer
    Compressibility factor for 1 mole of a van der Waals? gas at \[{{0}^{o}}C\]and 100 atmospheric pressure is found to be 0.5 the volume of gas molecules is :

    A) 2.0224                                  

    B) 1.4666

    C) 0.8542                                  

    D) 0.1119

    Correct Answer: D

    Solution :

    Compressibility factor \[(Z)=\frac{PV}{nRT}\] For ideal gas\[PV=nRT\]                      \[\therefore \]\[Z\ne 1\] For real gas \[PV\ne nRT\]\[\therefore \]\[Z\ne 1\] \[0.5=\frac{100\times V}{1\times 0.82\times 273}\] \[V=0.1119\,L\]


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